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The specific heat capacity of water is 4000 J/kg°C. How much heat will be required toraise the temperature of 7 kg of water from 7°C to 17°C?Express your answer in J.

Sagot :

Answer:

280000J

Explanation:

The heat required can be calculated using the following equation

[tex]Q=mC(T_2-T_1)[/tex]

Where m is the mass, so m = 7 kg, C is the specific heat capacity, so C = 4000 J/Kg °C, and T2 and T1 are the temperatures, so T1= 7 °C and T2 = 17°C.

Therefore, by replacing the values, we get:

[tex]\begin{gathered} Q=(7kg)(4000\text{ J/kg \degree C\rparen\lparen17 }\degree C-7\degree C) \\ Q=280000\text{ J} \end{gathered}[/tex]

Then, the answer is 280000J

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