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We need two points to graph a line.
Substituting with x = 0 into the equation and solving for y, we get:
[tex]\begin{gathered} 3y-2\cdot0=9 \\ 3y=9 \\ y=\frac{9}{3} \\ y=3 \end{gathered}[/tex]Then, the point (0, 3) lies on the line.
Substituting with x = 3 into the equation and solving for y, we get:
[tex]\begin{gathered} 3y-2\cdot3=9 \\ 3y-6=9 \\ 3y=9+6 \\ 3y=15 \\ y=\frac{15}{3} \\ y=5 \end{gathered}[/tex]Then, the point (3, 5) lies on the line.
To graph the line we need to locate these two points on the plane, and connect them with a line, as follows:
