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Sagot :
Answer:
2.38 g of oxygen (O2).
Explanation:
What is given?
Mass of potassium chlorate (KClO3) = 6.06 g.
Molar mass of KClO3 = 122.4 g/mol.
Molar mass of oxygen (O2) = 32 g/mol.
Step-by-step solution:
First, let's state the balanced chemical equation. Remember that the decomposition of a compound produces two or more products:
[tex]2KClO_3\rightarrow2KCl+3O_2.[/tex]Now, let's convert 6.06 g of KClO3 to moles using its molar mass:
[tex]6.06\text{ g KClO}_3\cdot\frac{1\text{ mol KClO}_3}{122.4\text{ g KClO}_3}=0.0495\text{ moles KClO}_3.[/tex]You can see in the chemical equation that 2 moles of KClO3 produce 3 moles of O2. By doing a rule of three with this data, we obtain that:
[tex]0.0495\text{ moles KClO}_3\cdot\frac{3\text{ moles O}_2}{2\text{ moles KClO}_3}=0.0743\text{ moles O}_2.[/tex]The final step is to convert from 0.0743 moles of O2 to grams using its molar mass, like this:
[tex]0.0743\text{ moles O}_2\cdot\frac{32\text{ g O}_2}{1\text{ }mol\text{ }O_2}=2.38\text{ g O}_2.[/tex]The answer is that we will produce 2.38 g of oxygen (O2) from the decomposition of 6.06 g of potassium chlorate (KClO3).
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