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What is the equation of a line that passes through points (0, 4) and (-4, -8)? O y=3x-4 O y= 2 x - 4 O y= 3 x+4 O y=2x+4

Sagot :

In this case, we'll have to carry out several steps to find the solution.

Step 01:

Data

point 1 (0, 4) x1 = 0 y1 = 4

point 2 (-4, -8) x2 = -4 y2= -8

equation of the line = ?

Step 02:

slope formula

[tex]m\text{ = }\frac{y2-y1}{x2-x1}[/tex][tex]m\text{ = }\frac{-8-4}{-4-0}=\frac{-12}{-4}=3[/tex]

point-slope form of the line

(y - y1) = m (x - x1)

(y - 4) = 3 (x - 0)

y - 4 = 3x

y = 3x + 4

The answer is:

The equation of the line is y = 3x + 4

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