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Sagot :
hello
the question here request we find the equation of line passing through point (-1, 2)
the first equation given is
[tex]y=-\frac{1}{3}x+6[/tex]passing through points (-1, 2)
equation of line is given as
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ m=-\frac{1}{3} \\ \end{gathered}[/tex]the points are (-1, 2)
[tex]\begin{gathered} x_1=-1 \\ y_1=2 \end{gathered}[/tex]now, let's substitute the values into the equation above
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-2=-\frac{1}{3}(x-(-1)) \\ y-2=-\frac{1}{3}(x+1) \\ y-2=-\frac{(x+1)}{3} \\ \text{cross multiply both sides} \\ 3(y-2)=-x-1 \\ 3y-6=x-1 \\ 3y=-x-1 \\ \text{divide both sides by the coeffiecient of y which is 3} \\ \frac{3y}{3}=\frac{-x-1}{3} \\ y=\frac{-x-1}{3} \\ y=-\frac{x}{3}-\frac{1}{3} \end{gathered}[/tex]
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