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Sagot :
[tex]\begin{equation*} 448.1 \end{equation*}[/tex]
1) Given that my car gets 22 miles per gallon, and I drive 498 miles I'll need to make reference to the emission rate of CO2 my car has: 19.8 lbs/gallon.
2) So, we can write out the following ratios. Firstly, we need to figure out how many gallons of gas were needed to drive 498 miles
[tex]\begin{gathered} 22miles--------1g \\ 498----------x \\ 22x=498 \\ x=\frac{498}{22} \\ x=22.63gallons \end{gathered}[/tex]Now, we can write out the following relationship:
[tex]\begin{gathered} 19.8lbs---1gallon \\ y------22.63 \\ \frac{19.8}{y}=\frac{1}{22.63} \\ \\ y=448.074\approx448.1\:\frac{lbs}{gallon} \end{gathered}[/tex]
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