Get expert advice and insights on any topic with IDNLearn.com. Get step-by-step guidance for all your technical questions from our knowledgeable community members.

What is the remainder when x3 – 3x2 – 37 is divided by x - 5?(A)3(B)-27(C) 0(D) 73(E) 13

Sagot :

Given data:

The given equation is x^3-3x^2-37.

The given expression can be written as,

[tex]\begin{gathered} x^3-3x^2-37=x^2(x-5)+2x(x-5)+10(x-5)+13 \\ x^3-3x^2-37=(x-5)(x^2+2x+10)+13 \end{gathered}[/tex]

Thus, when x^3-3x^2-37 is divide by (x-5) we get 13 as a remainder, so the correct option is (E).

Thank you for contributing to our discussion. Don't forget to check back for new answers. Keep asking, answering, and sharing useful information. Discover the answers you need at IDNLearn.com. Thanks for visiting, and come back soon for more valuable insights.