Solution:
Given:
[tex]6\frac{3}{8}-1\frac{5}{8}[/tex]step 1: Express each mixed number as improper fractions.
[tex]\begin{gathered} 6\frac{3}{8}=\frac{(6\times8)+3}{8} \\ \Rightarrow\frac{51}{8} \\ 1\frac{5}{8}=\frac{(1\times8)+5}{8} \\ \Rightarrow\frac{13}{8} \end{gathered}[/tex]step 2: Find the difference between the fractions.
[tex]\begin{gathered} \frac{51}{8}-\frac{13}{8} \\ \text{LCM is 8} \\ \text{thus,} \\ =\frac{51-13}{8} \\ =\frac{43}{8} \end{gathered}[/tex]step 3: Expressed the obtained fraction as a mixed number.
[tex]\frac{43}{8}\Rightarrow5\frac{3}{8}[/tex]Since the result of the above operation is not equal to
[tex]4\frac{3}{4}[/tex]The correct choice is No.
Given:
[tex]\frac{7}{12}+2\frac{1}{3}+1\frac{5}{6}[/tex]step 1: Express each mixed number as improper fractions.
[tex]\begin{gathered} 2\frac{1}{3}=\frac{(2\times3)+1}{3}=\frac{7}{3} \\ 1\frac{5}{6}=\frac{(1\times6)+5}{6}=\frac{11}{6} \end{gathered}[/tex]step 2: Find the sum of the fractions.
[tex]\begin{gathered} \frac{7}{12}+\frac{7}{3}+\frac{11}{6} \\ \text{LCM is 12} \\ \text{thus,} \\ =\frac{7+28+22}{12} \\ =\frac{57}{12} \\ =\frac{19}{4} \end{gathered}[/tex]step 3: Expressed the obtained fraction as a mixed number.
Thus,
[tex]\frac{19}{4}\Rightarrow4\frac{3}{4}[/tex]Since the result of the above operation is
[tex]4\frac{3}{4}[/tex]The correct choice is Yes.