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Sagot :
When we take a look at; (x + 6)(x - 6) = 0
x+6 = 0 or x-6 = 0
x=-6 or x=6
Similarly
(2x + 12)(2x - 12) = 0
Either (2x + 12) = 0 or (2x - 12)=0
2x = -12 or 2x =12
x=-6 or x=6
Therefore (x + 6)(x - 6) = 0 and (2x + 12)(2x - 12) = 0 has same pair of solutions
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