Answered

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(4k + 5) (k + 1)=0 please help me to this problem please.

Sagot :

[tex](4k+5)(k+1)=0[/tex][tex](4k)(k)+(4k)(1)+(5)(k)+(5)(1)=0[/tex][tex]4k^2+4k+5k+5=0[/tex][tex]4k^2+9k+5=0[/tex]

then applying the quadratic formula

[tex]k=\frac{-9\pm\sqrt[]{81-(4)(4)(5)}}{2(4)}=\frac{-9\pm1}{8}[/tex]

then the solutions of the equation will be K=-5/4 and K=-1

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