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Sagot :
Joe= 4 times as Goran = 4g = 4 (k-9)
Goran served 9 fewer than Katilin so = k -9
[tex]\begin{gathered} 123=4(k\text{ -9\rparen + \lparen k - }9)+k \\ \\ 123=4k\text{ - }36\text{ +}k\text{ -}9\text{ +k} \\ \\ 123=6k\text{ -45} \\ \\ 6k=123+45 \\ \\ 6k=168 \\ \\ k=\frac{168}{6}=28 \\ \\ \text{Kaitlyn has 28} \\ \\ Joe=\text{ 4\lparen k -9\rparen} \\ \text{= 4\lparen19\rparen = 76} \\ \\ Goran=k\text{ - 9 =} \\ \text{ 28-9=19} \end{gathered}[/tex]
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