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A line passes through the points (8,5) and (4,4). What is its equation im slope-intercept from?

Sagot :

Given the points ( 8 , 5 ) and ( 4 , 4 )

The general slop-intercept form of the equation of the line is:

y = mx + c

where m is the slope and c is y-intercept

The slope will be calculated as following:

[tex]\text{slope}=m=\frac{y2-y1}{x2-x1}=\frac{5-4}{8-4}=\frac{1}{4}[/tex]

So, the equation of the line will be:

[tex]y=\frac{1}{4}x+c[/tex]

Using the one of the given points to find the value of c

Let , we will use the point ( 4 , 4 )

so, when x = 4 , y = 4

[tex]\begin{gathered} 4=\frac{1}{4}\cdot4+c \\ 4=1+c \\ c=4-1=3 \end{gathered}[/tex]

So, the slope - intercept equation of the line is:

[tex]y=\frac{1}{4}x+3[/tex]