[tex]\begin{gathered} 100(x)^t \\ \\ x=1+r \end{gathered}[/tex]
Use the formula above to find the amount in account after t years
r is the interest rate in decimal form
After 10 years:
Jessica's account:
r= 0.02
[tex]100(1+0.02)^{10}=100(1.02)^{10}=121.90[/tex]
Tyshaun's account:
r= 0.025
[tex]100(1+0.025)^{10}=100(1.025)^{10}=128.01[/tex]
Subtract the final amounts:
[tex]Tyshaun^{\prime}saccount-Jessica^{\prime}saccount=128.01-121.90=6.11[/tex]
Then, after 10 years Tyshaun's initial deposit have earned $6.11 more money than Jessica's initial deposit.
Answer: 6.11
