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Answer:
2,300 people.
Explanation:
The sentence "decreasing at a constant rate" suggests a linear relationship.
• The population in 2010 = 5900 =>(0, 5900)
,• The population in 2012= 4700 =>(2, 4700)
First, determine the constant rate of the population's decrease.
[tex]\text{Rate}=\frac{5900-4700}{0-2}=\frac{1200}{-2}=-600[/tex]Thus, we can model the town's population using the linear function.
[tex]y=5900-600x[/tex]In 2016, that is, 6 years after 2010: x=6
[tex]y=5900-600(6)=5900-3600=2300[/tex]The population in 2016 will be 2,300 people.