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Given:
The magnitude of each charge is q1 = q2 = 1 C
The distance between them is r = 1 m
To find the force when distance is doubled.
Explanation:
The new distance is
[tex]\begin{gathered} r^{\prime}=\text{ 2r} \\ =2\times1 \\ =2\text{ }m \end{gathered}[/tex]The force can be calculated by the formula
[tex]F=k\frac{q1q2}{(r^{\prime})^2}[/tex]Here, k is the constant whose value is
[tex]k=9\times10^9\text{ N m}^2\text{ /C}^2[/tex]On substituting the values, the force will be
[tex]\begin{gathered} F=9\times10^9\times\frac{1\times1}{(2)^2} \\ =2.25\times10^9\text{ N} \end{gathered}[/tex]