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Sagot :
Given:
The probability of finding an elephant in a national park is 0.7.
The probability of finding a cheetah in a national park is 0.4.
The probability of finding an elephant or Cheetah or both is 0.8.
[tex]\begin{gathered} P(E)=0.7 \\ P(C)=0.4 \\ P(E\text{ or C or both)=0.8} \end{gathered}[/tex]a) The probability that both the animals will be spotted is,
[tex]\begin{gathered} P(E\text{ or C)=P(E)+P(C)-P(E and C)} \\ 0.8=0.7+0.4-\text{P(E and C)} \\ \text{P(E and C)}=0.3 \end{gathered}[/tex]b) The probability of Neither of the animal will be spotted is,
[tex]P(\text{not (E and C))=1-P(E and C)=1-0.3=0.7}[/tex]Answer:
a) probability is 0.3.
b) probability is 0.7.
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