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x+y+ 10 = 0Given:2х+у – 2 = 0

Sagot :

we have

x+y+10=0 --------> equation A

x^2+y-2=0 ------> equation B

Isolate the variable y in equation A and equation B

so

y=-10-x

y=2-x^2

equate both equations

-10-x=2-x^2

solve for x

x^2-x=2+10

x^2-x-12=0

Solve with the formula of quadratic equation

a=1

b=-1

c=-12

[tex]\begin{gathered} x=\frac{1\pm\sqrt[\square]{(-1^2)-4(1)(-12)}}{2} \\ \\ x=\frac{1\pm7}{2} \end{gathered}[/tex]

therefore

the values of x are

x=4 and x=-3

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