Given:
[tex]\angle ACD=35\degree,AD=15,DB=13\text{ and AC=CB.}[/tex]
Required:
We need to find the measure that is not possible for angle DCB.
Explanation:
The given triangle is isosceles.
Recall that the altitude from the apex of an isosceles triangle bisects the base into two equal parts and also bisects its apex angle into two equal angles.
[tex]\text{ We know that AD}\ne DB.[/tex]
The line DC does not bisect the side AB.
So the line does not bisect the angle ACB.
[tex]\angle ACD\ne\angle CDB[/tex][tex]Substitute\text{ }\angle ACD=35\degree.[/tex]
[tex]35\degree\angle CDB[/tex]
Final answer:
The angle of 35 degrees is not possible for angle CDB.
