Discover the best answers to your questions with the help of IDNLearn.com. Discover the information you need quickly and easily with our reliable and thorough Q&A platform.

A bear population is increasing by 5% each year. This year, there 43 bears. How many bears will there be next year? Round your answer to the nearest whole number.

Sagot :

Exponential Growth

If a population has exponential growth, starting from an initial population Po, then the future number of members of the population is given by:

[tex]P(t)=P_o\cdot(1+r)^t[/tex]

Where r is the growth rate and t is the time.

We are given the current population of bears Po = 43 and the increasing rate of r = 5% = 0.05 each year, thus the model can be written as:

[tex]\begin{gathered} P(t)=43\cdot(1+0.05)^t \\ \text{Calculating:} \\ P(t)=43\cdot(1.05)^t \end{gathered}[/tex]

Next year (t = 1), the population is expected to be:

[tex]\begin{gathered} P(1)=43\cdot(1.05)^1 \\ P(1)=43\cdot(1.05) \\ P(1)\approx45 \end{gathered}[/tex]

There will be 45 bears next year

We appreciate every question and answer you provide. Keep engaging and finding the best solutions. This community is the perfect place to learn and grow together. IDNLearn.com is your go-to source for accurate answers. Thanks for stopping by, and come back for more helpful information.