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Given
[tex]a_n=6n-8[/tex]To find: The first four terms of the sequence.
Explanation:
It is given that,
[tex]a_n=6n-8[/tex]Then,
For n=1,
[tex]\begin{gathered} a_1=6(1)-8 \\ =6-8 \\ =-2 \end{gathered}[/tex]For n=2,
[tex]\begin{gathered} a_2=6(2)-8 \\ =12-8 \\ =4 \end{gathered}[/tex]For n=3,
[tex]\begin{gathered} a_3=6(3)-8 \\ =18-8 \\ =10 \end{gathered}[/tex]For n=4,
[tex]\begin{gathered} a_4=6(4)-8 \\ =24-8 \\ =16 \end{gathered}[/tex]Hence, the first four terms of the sequence is -2, 4, 10, 16.