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Write an equation of the line that passes through point P and isperpendicular to the line with the given equation.P(0, 0), y = –9x – 1

Sagot :

First, we are going to calculate the slope of a line that is perpendicular to the one we are given.

Let m1 be the slope of the line y = -9x - 1

[tex]m1=-9[/tex]

The conditions for two lines to be perpendicular must be as follows

[tex]m1m2=-1[/tex][tex]m2=-1/m1[/tex][tex]m2=-\frac{1}{-9}=\frac{1}{9}[/tex]

Now we need to calculate the y-axis cut (b)

[tex]b=y-m2x[/tex][tex]b=0-\frac{1}{9}\cdot(0)[/tex][tex]b=0[/tex]

The equation of the line would be the following

[tex]y=\frac{1}{9}x[/tex]

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