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What is the equation of the line that passes through the point (-2, 1) and has aslope of 3/2?

Sagot :

We will find the equation that passes through the point (-2, 1) & m = 3/2, using the following expression:

[tex]y-y_1=m(x-x_1)[/tex]

Here, the point is (x1, y1) and the slope m, we will replace and solve for y:

[tex]y-1=\frac{3}{2}(x-(-2))\Rightarrow y-1=\frac{3}{2}x+3[/tex][tex]\Rightarrow y=\frac{3}{2}x+4[/tex]

So, the equation is y = 3/2x + 4.

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