We have a data set summarized as a stem-and-leaf plot
Recall that a stem and leaf diagram displays numerical data by separating each data point into a "leaf" (usually the last digit) and a "stem" (the leading digit(s))
In this case, we have 4 stems
In the first stem, we have 8 leaves that are to say 8 data
In the second stem, we have 16 data, in the third stem we have 5 data and in the last stem we have 3 data
First
n is the sum of all the data, n gives us the following
[tex]\begin{gathered} n=8+16+5+3 \\ n=32 \end{gathered}[/tex]The answer is n=32 data set
Second
Now, the last class corresponds to the last stem, the minimum value of the last class is 80
8 is the stem, and the minimum leave is 0 for this reason the number is 80
Third
The modal class refers, in a table of grouped data, to the class or interval that has the highest frequency
In this case, is the 6 stem, and as frequency is 16
The frequency is the number of data to the associated group
Fourth
To find out how many numbers are greater than 60 we must count all data greater than 60
When we do this we know that the groups on stems 7 and 8 are inside the constraint and those on stem 5 are outside
Now we count the possible root 6 data with leaves that are greater than 0, when we do this we have 13 data
Then the data that is greater than 60 is:
[tex]5+3+13=21[/tex]This answer is 21 data