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What is the length of the unknown leg to the nearest tenth?T 1610

What Is The Length Of The Unknown Leg To The Nearest TenthT 1610 class=

Sagot :

Ans:12.5

Using Pythagoras theorem in the triangle,

[tex]\begin{gathered} \text{Hypotenuse}^2=Base^2+Altitude^2 \\ 16^2=10^2+a^2 \\ 256=100^{}+a^2 \\ 256-100=a^2 \\ 156=a^2 \\ \sqrt[]{156}=a \\ 12.5=a \end{gathered}[/tex]

Therefore, length of the unknown leg, a=12.5.

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