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Using the pythagorean theorem we have:
[tex]\begin{gathered} a^2+b^2=c^2\text{ (}a\text{ and b are legs and c is the hypotenuse)} \\ (1)^2+b^2=(19)^2\text{ (Replacing the values)} \\ 1+b^2=361\text{ (Raising the numbers to the power of 2)} \\ b^2=361-1\text{ (Subtracting 1 from both sides of the equation)} \\ b^2=360\text{ (Subtracting)} \\ b=\sqrt[]{360}\text{ (Taking the square root)} \\ b=18.97 \\ \text{The answer is 1}9.0\text{ rounding to the nearest tenth. } \end{gathered}[/tex]