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Sagot :
As per given by the question,
There are given that the point,
(-1, -1), (2, -5), (-3, 8), (4, 13) and (2, -16).
Now,
If we draw the all point on the graph paper, then
For the point first, (-1, -1)
For point first, from the x axis, there is only one image in y-axis.
For point second(2, -5), from the x-axis, there is only one image in y-axis.
For point third(-3, 8), from the x-axis there is also only one image in y-axis.
For point (4, 13), from the x-axis there is also only one image in y axis.
And,
for point fifth(2, -16), from the x-axis there is two image in y-axis, because one image already exists in point (2, -5)
So,
According to the function concept,
Each x coordinate have must be only one image in y coordinate.
Now,
In given point, there are two images in y coordinate for x coordinate.
So,
The given set of point is does not represent the function.
Hence, the given statement is False.
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