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The sample space is composed of the following outcomes:
Notice that the size of the sample space is 36.
Now, the sum is less than 7 for the following results:
(1,1), (1,2), (1,3), (1,4), (1,5)
(2,1), (2,2), (2,3), (2,4)
(3,1), (3,2), (3,3)
(4,1), (4,2)
(5,1)
thus, the probability of rolling the sum less than 7 would be:
[tex]\frac{15}{36}=\frac{5}{12}[/tex]we can conclude that the correct answer is:
Answer:[tex]\frac{5}{12}[/tex]