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A)
The inequation is as follows:
[tex]4x-2<6[/tex]To get de solution, we can do:
[tex]\begin{gathered} 4x-2<6 \\ 4x<6+2 \\ 4x<4 \\ x<\frac{4}{4} \\ x<1 \end{gathered}[/tex]To give the solution in a number line, we first draw a line, marke the "1" in it and mark the line belowe "", since the solution is the numbers less than 1. Also, the mark in the "1" should be a open dot, meaning, it is not filled, which indicates that "1" is not included in the set.
So:
B) To write the solution in interval notatio, we put the start and the end of the set. Since it goes all the way to minus infinity, we put as:
[tex](-\infty,1)[/tex]When it is infinite, we use "(" to indicate it is open set in this side. The other ")", beside the "1" indicates that "1" is not included.
