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For this problem we use the formula for the volume of a cone
[tex]V=\frac{\pi}{3}\cdot r^2\cdot h[/tex]Substituting, and using pi=3.14 we get
[tex]V=\frac{3.14}{3}\cdot(6.1\operatorname{cm})^2\cdot10.4\operatorname{cm}=405.04cm^3[/tex]