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Sagot :
A bar has the form of a rectangular prism, the volume of this kind of figure is given by the following formula:
[tex]V=l\times w\times h[/tex]Where l is the length, w is the width and h is the height of the bar.
Let's call l1, w1 and h1 to the length, width and height of the regular chocolate bar, by replacing them into the above formula we get 38.5 cubic centimeters for the volume:
[tex]38.5=l1\times w1\times h1[/tex]Now, Let's call l2, w2, and h2 to the length, width, and height of the special edition chocolate bar. We are told that the dimensions of this bar are two times the dimensions of the regular one, then:
l2 = 2×l1
w2 = 2×w1
h2 = 2×h1
By dividing by two on both sides of these expressions, we get:
[tex]\begin{gathered} l1=\frac{l2}{2} \\ w1=\frac{w2}{2} \\ h1=\frac{h2}{2} \end{gathered}[/tex]By replacing these into the equation of the volume for the regular bar, we get:
[tex]\begin{gathered} 38.5=\frac{l2}{2}\times\frac{w2}{2}\times\frac{h2}{2} \\ 38.5=\frac{l2\times w2\times h2}{2\times2\times2^{}} \\ 38.5=\frac{l2\times w2\times h2}{8^{}} \\ 38.5\times8=l2\times w2\times h2 \\ 308=l2\times w2\times h2 \\ l2\times w2\times h2=308 \\ V2=308 \end{gathered}[/tex]Then, the volume of the special edition bar (V2) equals 308 cubic centimeters
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