Answered

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If x^2 - 9 = 0, then x canonly be equal to 3. True or false?

If X2 9 0 Then X Canonly Be Equal To 3 True Or False class=

Sagot :

Solution

Given

[tex]x^2-9=0[/tex]

Note: Difference of Two Square

[tex]a^2-b^2=(a-b)(a+b)=0[/tex]

Now, using the difference of two squares

[tex]\begin{gathered} x^2-9=0 \\ x^2-3^2=0 \\ (x-3)(x+3)=0 \\ \text{Either} \\ x-3=0 \\ x=3 \\ or \\ x+3=0 \\ x=-3 \\ \text{Therefore,} \\ x=3,-3 \end{gathered}[/tex]

Therefore, the answer is False because apart from x = 3, x can also be equal to -3

FALSE

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