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Distance = 5 units
Explanation:The points on the graph: (2, 5) and (7, 5)
We would apply the distance formula:
[tex]dis\tan ce\text{ = }\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}[/tex][tex]\begin{gathered} x_1=2,y_1=5,x_2=7,y_2\text{ = }5 \\ \text{distance = }\sqrt[]{(5-5)^2+(7-2)^2\text{ }} \end{gathered}[/tex][tex]\begin{gathered} \text{distance = }\sqrt[]{(0)^2+(5)^2} \\ \text{distance = }\sqrt[]{0+25} \\ \text{distance = }\sqrt[]{25} \\ \text{distance = 5} \end{gathered}[/tex]