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Sagot :
Solution:
Let the bob's speed be represented below as
[tex]=b[/tex]Since bob drives 4mph faster than jane, janes, speed will be represented below as
[tex]jane=b-4[/tex]The total speed will be calculated below as
[tex]b+b-4[/tex]The time taken is given below as
[tex]=2hrs[/tex]The total distance apart is given below as
[tex]=116mi[/tex]Concept:
Using the formula below, we will have
[tex]distance=speed\times time[/tex]By substituting the values, we will have
[tex]\begin{gathered} distance=2(b+b-4) \\ 2(b+b-4)=116 \end{gathered}[/tex]By simplifying further, we will have
[tex]\begin{gathered} 2(b+b-4)=116 \\ 2(2b-4)=116 \\ 2b-4=\frac{116}{2} \\ 2b-4=58 \\ 2b=58+4 \\ \frac{2b}{2}=\frac{62}{2} \\ b=31mi\text{ }per\text{ }hr \end{gathered}[/tex]Substitute b=31 in the equation below
[tex]\begin{gathered} jane=b-4 \\ jane=31-4 \\ jane=27\text{ }mi\text{ }per\text{ }hr \end{gathered}[/tex]Hence,
Jane is driving at 27 miles per hour
Bob is driving at 31 miles per hour
The final answer is TRUE
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