Solution.
The prolem will be soved using binomial distribution concept
The binomial formula is
For the question before us,
[tex]\begin{gathered} n=6 \\ x=3 \\ p=\frac{2}{6}=\frac{1}{3} \\ q=1-\frac{1}{3}=\frac{2}{3} \end{gathered}[/tex][tex]\begin{gathered} P(3)=^6C_3(\frac{1}{3})^3(\frac{2}{3})^3 \\ =20\text{ x }\frac{1}{27}\text{ x }\frac{8}{27} \\ =\frac{160}{729} \\ =0.2195(4\text{ decimal places\rparen} \end{gathered}[/tex]
You
