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The function f is defined by f(x)=50⋅3x. The function g is defined by g(x)=a⋅bx. The graphs of f and g are given below. How does a, from function g(x) compare to 50 from function f(x)?

Sagot :

So, the function f is defined as:

[tex]f(x)=50(3)^x[/tex]

And the function g has the form:

[tex]g(x)=a(b)^x[/tex]

Given that the graphs of f and g are:

We could compare the value of "a" from function g(x) to 50 from function f(x) as follows:

Notice that when x=0:

[tex]\begin{gathered} f(0)=50\cdot(3^0)=50 \\ g(0)=a\cdot(b^0)=a \end{gathered}[/tex]

As you can see from the graph, the function g is greater than the function f at the point x=0, so, comparing a with 50, we could affirm that:

[tex]a>50[/tex]

View image JeriyahV457205
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