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The town's population increased from 80,000 to 90,000 in ten years. What was the percent of increase?

Sagot :

[tex]12.5\%[/tex]

1) We can solve this problem by writing the following ratios and then cross multiplying

2) Note that we're going to consider 80,000 as the 100%

[tex]\begin{gathered} 80,000-------100\% \\ 90,000-------x \\ x=\frac{90000\cdot100}{80000} \\ x=\frac{90000}{800}=112.5 \end{gathered}[/tex]

We can now subtract 100 from that 112.5

[tex]112.5\%-100\%=12.5\%[/tex]

3)Thus the percent of increase in that town was:

[tex]12.5\%[/tex]

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