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Calculate the ️Hf for the following reaction:8 Al(s) + 3 Fe3O4(s) ---> 4 Al2O3(s)+ 9 Fe(s)Al2O3(s) ️Hf = -1669.8Fe3O4(s) ️Hf = -1120.9 kJ/mol

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Answer

Explanation

Given data:

8Al(s) + 3Fe₃O₄(s) ---> 4Al₂O₃(s)+ 9Fe(s)

Al₂O₃(s) ️Hf = -1669.8kJ/mol

Fe₃O₄(s) ️Hf = -1120.9 kJ/mol​

Step-by-step solution:

The ️Hf for the reaction can be calculated using the formula below:

[tex]\Delta H_f=\sum^.\Delta H_f(product)-\sum^.\Delta H_f(reactants)[/tex]

For Al(s) and Fe(s), their ΔHf is arbitrary zero.

Therefore, the ore, the ️Hf for the is:reaction

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