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without solving detemine whether the solution to the equation 32531÷y=160 is greater than or less than 200 explain

Sagot :

[tex]\frac{32531}{y}=160[/tex]

y is greatar than 200 because

[tex]\frac{32531}{200}=\frac{325.31}{2}[/tex]

half od 325.31 is greater than 160 so we need a number grater than 200 to obtaion 160 in the result

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