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Sagot :
[tex]y=\frac{7}{8}x+\frac{57}{8}[/tex]
Explanation
Step 1
find the slope of the given line
[tex]y=\frac{7}{8}x+8[/tex]this equation is in the form, slope -intercept
[tex]y=mx+b[/tex]where m is the slope , so
[tex]\begin{gathered} y=\frac{7}{8}x+8\Rightarrow y=\text{ mx+b} \\ hence \\ m=slope=\frac{7}{8} \end{gathered}[/tex]Step 2
2 lines are parallel if the slope is the same,so we are looking for a line with slope 7/8 and the point c(1,8) is part of the line
use
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ \text{where P1(x}_1,y_1)\text{ is a known point of the line} \end{gathered}[/tex]then
Let
P1=C=(1,8)
slope=7/8
now, replace
[tex]\begin{gathered} y-y_1=m(x-x_1) \\ y-8=\frac{7}{8}(x-1) \\ y-8=\frac{7}{8}x-\frac{7}{8} \\ \text{add 8 in both sides} \\ y-8+8=\frac{7}{8}x-\frac{7}{8}+8 \\ y=\frac{7}{8}x+\frac{57}{8} \end{gathered}[/tex]I hope this helps you
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