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The given inequality is:
[tex]\begin{gathered} \frac{1}{3}x-(x+5)\geq7 \\ \frac{1}{3}x-x-5\geq7 \\ -\frac{2}{3}x-5\geq7 \\ -\frac{2}{3}x\geq7+5 \\ -\frac{2}{3}x\geq12 \\ \text{ Multiply both sides by }-\frac{3}{2}\text{ and change the sign of the inequality to }\leq \\ x\leq12\times(-\frac{3}{2}) \\ x\leq-18 \end{gathered}[/tex]Therefore, the correct answer is choice C:
Mo is correct
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