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Which are the center and radius of the circle with equation (x+5)^2+ (y-4)^2= 9?

Which Are The Center And Radius Of The Circle With Equation X52 Y42 9 class=

Sagot :

The general equation of a circle is:

[tex](x-a)^2+(y-b)^2=r^2[/tex]

where:

(a, b) = coordinates of the center of the circle

r = radius of the circle

Now, the equation given in the question, which is:

[tex](x+5)^2+(y-4)^2=9[/tex]

Can be re-written as follows:

[tex]\begin{gathered} (x+5)^2+(y-4)^2=9 \\ \Rightarrow(x-(-5))^2+(y-4)^2=3^2 \end{gathered}[/tex]

Now, we can easily compare the resulting expression with the general equation of a circle.

On doing so, we have that:

(a, b) = (-5, 4)

r = 3

Thus, the center of the circle is (-5, 4) and the radius is 3

Therefore, the correct answer is: Option C