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Hello!
The exercise asks for a quadratic equation with solutions 6 and -1.
To obtain it, we can write it as a product of two polynomials.
We will write X and the root with the inverse sign, as the formula below:
(x - 6) * (x - -1) = 0
So, we will have:
[tex](x-6)\cdot(x+1)=0[/tex]This is the factored form.
If you want the quadratic equation, you also can solve it by distributive property:
[tex]x^2-5x-6=0[/tex](x -6) * (x +1) = 0