Connect with knowledgeable individuals and find the best answers at IDNLearn.com. Ask your questions and get detailed, reliable answers from our community of knowledgeable experts.

What is an equation of the line that passes through the point (-1,6) and is parallelto the line 2x + y = 9?

Sagot :

First, solve the given equation for y:

2x + y = 9

y = -2x + 9

the slope of the equation is m =-2.

Now, consider that all parallel lines have the same slope, then, the slope of the required line is m = -2.

Next, use the following general equation for a line:

y - yo = m(x - xo)

where (xo,yo) is any point on the line. Replace (xo,yo) = (-1,6) with m=-2 into the previous equation and solve for y:

y - 6 = -2(x - (-1))

y - 6 = -2x - 2

y = -2x - 2 + 6

y = -2x + 4

Hence, the equation of the line which crosses through the point (-1,6) and parallel to 2x + y = 9 is y = -2x + 4