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4. Law of Acceleration A 1500 kg car is forced to stop suddenly. If it was originally moving at 16 m/s and stops ina time of 4.7...What is the car's acceleration?How much net force is required?

Sagot :

In order to determine the acceleration of the car use the following formula:

[tex]v=v_o-at_{}[/tex]

where,

vo: initial velocity = 16 m/s

v: final velocity = 0 m/s

t: time = 4.7 s

a: acceleration = ?

Solve the equation above for a and replace the values of the other parameters:

[tex]a=\frac{v_o-v}{t}=\frac{\frac{16m}{s}-\frac{0m}{s}}{4.7s}=\frac{3.40m}{s^2}[/tex]

Hence, the acceleration of the car is 3.40 m/s^2, or if you consider that the car is deccelerating, it is -3.40 m/s^2.

To calculate the net required force, use the Newton second law:

[tex]F=ma[/tex]

where,

m: mass of the car = 1500 kg

F: force = ?

Replace the previous values of the parameters into the expression for F:

[tex]F=(1500kg)(\frac{3.40m}{s^2})=5100N[/tex]

Hence, the required force is 5100N