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Sagot :
Answer:
The Perimeter of the new shape is increased by a factor of 4.36
Explanation:
We were given a square having a side length of 7.3in
[tex]\begin{gathered} Area=length^2 \\ Area=7.3^2 \\ Area=53.29in^2 \\ \\ Per\imaginaryI meter=4\times length \\ Per\imaginaryI meter=4\times7.3 \\ Per\imaginaryI meter=29.2in \end{gathered}[/tex]If the area is multiplied by 19. Given by:
[tex]\begin{gathered} New\text{ }Area=53.29\times19 \\ New\text{ }Area=1012.51in^2 \\ Length=\sqrt{1012.51} \\ Length=31.8in \end{gathered}[/tex]The new side length is 31.8 inches
The new perimeter is given by:
[tex]\begin{gathered} New\text{ }Perimeter=4\times31.8new\text{ }length \\ Perimeter=127.2 \\ Perimeter=127.2in \end{gathered}[/tex]We will proceed to check what happens to the perimeter as shown below:
[tex]\begin{gathered} =\frac{New\text{ perimeter}}{Old\text{ perimeter}} \\ =\frac{127.2}{29.2} \\ =4.3562\approx4.36 \\ =4.36 \end{gathered}[/tex]The Perimeter of the new shape is increased by a factor of 4.36
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