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Sagot :
[tex]\begin{gathered} \text{Let 'D' represent the distance travelled by the car} \\ \text{Let 'A' represent the amount of gasoline it uses.} \end{gathered}[/tex][tex]\begin{gathered} \text{Thus,} \\ D\propto A \\ D=KA\text{ where 'K' is a constant} \end{gathered}[/tex][tex]\begin{gathered} \text{when D=476 miles, A=17 gallons} \\ \text{Thus,} \\ D=KA \\ 476=K\times17 \\ K=\frac{476}{17} \\ K=28 \end{gathered}[/tex][tex]\begin{gathered} We\text{ are to find 'D' when 'A' is 15 gallons} \\ \text{Thus,} \\ D=KA \\ D=28\times15 \\ D=420\text{ miles} \end{gathered}[/tex]
Hence, the number of miles traveled by car, when it has gasoline of 15 gallons is 420 miles
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