Discover new knowledge and insights with IDNLearn.com's extensive Q&A database. Join our community to receive prompt and reliable responses to your questions from knowledgeable professionals.
Sagot :
Solution:
Given the sequence;
[tex]-2,1,4,7,10,...[/tex]The nth term of an arithmetic sequence is;
[tex]\begin{gathered} a_n=a_1+(n-1)d \\ \\ Where\text{ }a_1=first\text{ }term,d=common\text{ }difference \end{gathered}[/tex]The common difference, d, is the difference between the consecutive terms of an arithmetic sequence.
[tex]\begin{gathered} d=a_2-a_1 \\ \\ Where\text{ }a_2=second\text{ }term \end{gathered}[/tex]Given;
[tex]\begin{gathered} a_2=1,a_1=-2 \\ \\ d=1-(-2) \\ \\ d=3 \end{gathered}[/tex]Thus, the 14th term is;
[tex]\begin{gathered} n=14,d=3,a_1=-2 \\ \\ a_{14}=-2+(14-1)(3) \\ \\ a_{14}=-2+(13)(3) \\ \\ a_{14}=-2+39 \\ \\ a_{14}=37 \end{gathered}[/tex]ANSWER: 37
We value your presence here. Keep sharing knowledge and helping others find the answers they need. This community is the perfect place to learn together. IDNLearn.com has the solutions to your questions. Thanks for stopping by, and come back for more insightful information.
