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alonzo, bob, and casper work bussing tables at a restaurant. alonzo has a 50% chance, bob has a 15% chance, and casper has a 35% chance of bussing tables in the middle area of the restaurant. if alonzo is bussing tables, he has a 6% chance of breaking a dish. if bob is bussing tables, he has a 2% chance of breaking a dish. finally, if casper is bussing tables, he has a 4% chance of breaking a dish. if there is a broken dish in the middle of the restaurant, what is the probability it was broken by bob?

Sagot :

KhiradAfaqidn

The probability was broken by Bob is, 0.003 or 3%.

What is probability?

Mathematical explanations of the likelihood that an event will occur or that a statement is true are referred to as probabilities. A number between 0 and 1 represents the likelihood of an event, with 0 generally denoting impossibility and 1 denoting certainty.

Alonzo, Bob, and Casper are each assigned three chances to bus tables and to fix any broken dishes, respectively.

P(Alonzo bussing tables) = 50% = 0.5

P(Bob bussing tables) = 15% = 0.15

P(Casper bussing tables) = 35% = 0.35

P(Alonzo breaking a dish) = 6% = 0.06

P(Bob breaking a dish)  = 2% = 0.02

P(Casper breaking a dish)  = 4% = 0.04

As the likelihood of dish breakage does not change with the busing of the tables, this is all about independent events.

Consequently, P(A and B) = P(A) + P (B)

So, if a dish is broken, the likelihood that Bob broke it is;

P(Bob breaking dishes and busing tables) = P(Bob busing tables) x P (Bob breaking a dish)

                                                                       = 0.15 x 0.02

                                                                       = 0.003

P(Bob breaking dishes and busing tables)  = 0.003 0r 0.3%

Hence, the probability was broken by Bob is, 0.003 or 3%.

To know more about the probability, click on the link

https://brainly.com/question/24756209

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