Zburris2004idn
Answered

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9. When 1.10 g of magnesium reacted with unlimited amount of HCl, the products were
hydrogen gas and magnesium chloride. What volume of hydrogen gas would be collected
if the reaction had been run at STP?

Sagot :

As per the balanced equation of the reaction one mole of Mg give s one mole of H2. 1.10 g of magnesium is 0.045 moles. Thus it gives 0.045 moles of H2 which is 1.02 litres.

What is magnesium chloride?

Magnesium chloride is an ionic compound formed by the reaction of magnesium metal with two moles of hydrochloric acid. The reaction also produce one mole  hydrogen gas.

The atomic mass of magnesium is 24 g/mol. Thus number of moles in 1.10 g is 1.10/24 = 0.045 moles.

As per the reaction equation one mole of magnesium gives one mole of hydrogen gas. Thus 0.045 moles of magnesium gives 0.045 moles of hydrogen gas.

At STP, the volume of one mole of any gas will be equal to 22.4 L. Thus volume of 0.045 moles of hydrogen at STP is:

volume = 0.045 × 22.4

             =1.02 L.

Hence, the volume of hydrogen produce here is 1.02 L.

To find more on magnesium, refer here:

https://brainly.com/question/1533548

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