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a ball is kicked with a velocity of 15 m/s at an angle of 60o to the horizontal. the time, in seconds, the ball takes to reach the highest point of its path is:

Sagot :

The time taken by the ball kicked with a velocity of 15 m/s at an angle of 60° to the horizontal to reach the highest point of its path is 2.66 s

t = 2 u sin θ / g

t = Total time of flight

u = Initial velocity

θ = Angle of projection

g = Acceleration due to gravity

u = 15 m / s

θ = 60°

g = 9.8 m / s²

t = 2 * 15 * sin 60° / 9.8

t = 26.1 / 9.8

t = 2.66 s

The time taken by a projectile to reach the highest point will be equal to the time taken by the projectile to reach the ground from there.

T = t / 2

T = 2.66 / 2

T = 1.33 s

Therefore, the time taken by the ball to reach the highest point of its path is 1.33 s

To know more about projectile motion

https://brainly.com/question/11049671

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